16x^2-64=120x

Solution for 16x^2-64=120x equation:

16x^2-64=120x

We move all terms to the left:

16x^2-64-(120x)=0

a = 16; b = -120; c = -64;
Δ = b2-4ac
Δ = -1202-4·16·(-64)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-136}{2*16}=\frac{-16}{32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+136}{2*16}=\frac{256}{32}
=8
$